Blog: CS601 Solution Assignment

Solution 1

No. of Voice Channels	Data Rate in Mbps	Type of T/E line used	Total No. of T/E lines
50	3.2Mbps	T1 /E1	3 lines of T1 or 2 lines of E1
90	5.76Mbps	T2 /E1	1 Line of T2 or 3 lines of E1
140	8.96Mbps	T2+T1/E1+E2	I line of T2 + 2 lines of T1 or  1 line E1 + 1 lines E2
195	12.48Mbps	T2+T1 /E-1	1 line of T1 + 2 lines of T2 or 7 lines of E1
600	38.4Mbps	T3/E2+E3	1 line of T3 or 1 line of E2 +  1 line of E3

Solution 2

Our message reaches with out alteration because our reminder is nonzero

The message =1010111001100010

Polynomial (Devisor) x⁴ + x³ + x + 1

Binary (Devisor)

Therefore Devisor = 11011

.

Whole strings (original message + 0000) is 10101110011000100000

Sender Side

 

Receiver Side

 

Message + CRC

1 0 1 0 1 1 1 0 0 1 1 0 0 0 1 0 +1 1 1 1 = 1 0 1 0 1 1 1 0 0 1 1 0 0 0 1 0 1 1 1 1

1 1 0 1 0 0 0 1 1 0 0 0 1 1 0 1